4.9x^2+13x-53=0

Solution for 4.9x^2+13x-53=0 equation:

4.9x^2+13x-53=0

a = 4.9; b = 13; c = -53;
Δ = b2-4ac
Δ = 132-4·4.9·(-53)
Δ = 1207.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{1207.8}}{2*4.9}=\frac{-13-\sqrt{1207.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{1207.8}}{2*4.9}=\frac{-13+\sqrt{1207.8}}{9.8}
$